Advertisements
Advertisements
प्रश्न
A solid weighs 105 kgf in air. When completely immersed in water, it displaces 30,000 cm3 of water, calculate relative density of solid.
Advertisements
उत्तर
Weight of solid in air =105 kgf
Volume of solid = Volume of water displaced = 30000 cm3
= 30000 x 10-6 m3 = 0.03 m3
pw = Density of water = 1000 kgm-3
Wt. of water displaced by solid.
`"V"rho_"w""g" = 0.03 xx 1000 xx "g" = 30 "kgf"`
R.D. of solid = `"Weight of solid in air"/"Weight of water displaced by solid"`
`= 105/30 = 3.5`
APPEARS IN
संबंधित प्रश्न
How does the density of material of a body determine whether it will float or sink in water?
A solid of density 5000 kg m-3 weighs 0.5 kgf in air. It is completely immersed in water of density 1000 kg m-3. Calculate the apparent weight of the solid in water.
How are the (i) Mass, (ii) Volume and (iii) Density of a metallic piece affected, if at all, with an increase in temperature?
Relative density of a substance is expressed by comparing the density of that substance with the density of :
A solid weighs 1.5 kgf in air and 0.9 kgf in a liquid of density 1.2 × 103 kg m-3. Calculate R. D. of solid.
A solid weighs 32 gf in air and 28.8 gf in water. Find: (i) The volume of solid, (ii) R.D. of solid and (iii) The weight of solid in a liquid of density 0.9 g cm-3.
A stone of density 3000 kgm3 is lying submerged in water of density 1000 kgm3. If the mass of stone in air is 150 kg, calculate the force required to lift the stone. [g = 10 ms2]
A solid of density 7600 kgm3 is found to weigh 0.950 kgf in air. If 4/5 volume of solid is completely immersed in a solution of density 900 kgm3, find the apparent weight of solid in a liquid.
A cube of the lead of side 8 cm and R.D. 10.6 is suspended from the hook of a spring balance. Find the reading of spring balance. The cube is now completely immersed in sugar solution of R.D. 1.4. Calculate the new reading of spring balance.
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
