Advertisements
Advertisements
प्रश्न
A solid weighs 120 gf in air and and 105 gf when it is completely immersed in water. Calculate the relative density of solid.
Advertisements
उत्तर
Weight of solid in air , W1 = 120 gf
Weight of solid when completely immersed in water W2 = 105 gf
R.D. of solid = `W_1/(W_1 - W_2) xx "R.D. of water"`
R.D. of solid = `120/(120 - 105) xx 1`
R.D. of solid = 8
APPEARS IN
संबंधित प्रश्न
Complete the following sentence.
Density in kg m-3 = ............ × density in g cm-3
What do you understand by the term relative density of a substance?
Differentiate between density and relative density of a substance.
A glass cylinder of length 12 x 10-2 m and area of crosssection 5 x 10-4 m2 has a density of 2500 kgm-3. It is immersed in a liquid of density 1500 kgm-3, such that 3/8. of its length is above the liquid. Find the apparent weight of glass cylinder in newtons.
A solid of R.D. 4.2 is found to weigh 0.200 kgf in air. Find its apparent weight in water.
A cube of the lead of side 8 cm and R.D. 10.6 is suspended from the hook of a spring balance. Find the reading of spring balance. The cube is now completely immersed in sugar solution of R.D. 1.4. Calculate the new reading of spring balance.
Calculate the mass of a body whose volume is 2m3 and relative density is 0.52.
A piece of metal weighs 44.5 gf in air, 39.5 gf in water. What is the R.D. of the metal?
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
