Advertisements
Advertisements
प्रश्न
Advertisements
उत्तर
Density of mercury = 13600 Kgm-3.
Density of water at 4oC = 1000 kg m-3.
Relative density = density of substance /density of water at 40C.
Relative density of mercury = 13600 Kgm-3/1000 kg m-3 = 13.6.
APPEARS IN
संबंधित प्रश्न
A body of volume V and density ρ is kept completely immersed in a liquid of density ρL. If g is the acceleration due to gravity, then write expressions for the following:
(i) The weight of the body, (ii) The upthrust on the body,
(iii) The apparent weight of the body in liquid, (iv) The loss in weight of the body.
A sphere of iron and another sphere of wood of the same radius are held under water. Compare the upthrust on the two spheres.
[Hint: Both have equal volume inside the water].
A solid of density 5000 kg m-3 weighs 0.5 kgf in air. It is completely immersed in water of density 1000 kg m-3. Calculate the apparent weight of the solid in water.
What do you understand by the term relative density of a substance?
The unit of relative density is :
Calculate the mass of a body whose volume is 2 m3 and relative density is 0.52.
A solid weighs 1.5 kgf in air and 0.9 kgf in a liquid of density 1.2 × 103 kg m-3. Calculate R. D. of solid.
A solid weighs 120 gf in air and and 105 gf when it is completely immersed in water. Calculate the relative density of solid.
A piece of wax floats in brine. What fraction of its volume will be immersed?
R.D. of wax = 0.95, R.D. of brine = 1.1.
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
