Advertisements
Advertisements
प्रश्न
A piece of stone of mass 113 g sinks to the bottom in water contained in a measuring cylinder and water level in cylinder rises from 30 ml to 40 ml. Calculate R.D. of stone.
Advertisements
उत्तर
Mass of stone = 113 g
Rise in water level = (40 - 30) ml = 10 ml
This rise is equal to the space occupied (volume) by the stone .
∴ volume of stone = 10 cm-3
Density of stone in C.G.S. = `"Mass"/"Volume" = 113/10 = 11.3` gcm-3
R.D. = 11.3
APPEARS IN
संबंधित प्रश्न
What is the unit of relative density?
The density of iron is 7.8 x 103 kg m-3. What is its relative density?
A piece of stone of mass 15.1 g is first immersed in a liquid and it weighs 10.9 gf. Then on immersing the piece of stone in water, it weighs 9.7 gf. Calculate:
- The weight of the piece of stone in air,
- The volume of the piece of stone,
- The relative density of stone,
- The relative density of the liquid.
A solid weighs 32 gf in air and 28.8 gf in water. Find: (i) The volume of solid, (ii) R.D. of solid and (iii) The weight of solid in a liquid of density 0.9 g cm-3.
A body of mass 70 kg, when completely immersed in water, displaces 20,000 cm3 of water. Find: (i) The weight of body in water and (ii) The relative density of material of the body.
A solid of R.D. 4.2 is found to weigh 0.200 kgf in air. Find its apparent weight in water.
A cube of the lead of side 8 cm and R.D. 10.6 is suspended from the hook of a spring balance. Find the reading of spring balance. The cube is now completely immersed in sugar solution of R.D. 1.4. Calculate the new reading of spring balance.
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
