Advertisements
Advertisements
प्रश्न
A piece of stone of mass 113 g sinks to the bottom in water contained in a measuring cylinder and water level in cylinder rises from 30 ml to 40 ml. Calculate R.D. of stone.
Advertisements
उत्तर
Mass of stone = 113 g
Rise in water level = (40 - 30) ml = 10 ml
This rise is equal to the space occupied (volume) by the stone .
∴ volume of stone = 10 cm-3
Density of stone in C.G.S. = `"Mass"/"Volume" = 113/10 = 11.3` gcm-3
R.D. = 11.3
APPEARS IN
संबंधित प्रश्न
A sphere of iron and another of wood, both of same radius are placed on the surface of water. State which of the two will sink? Give a reason for your answer.
How does the density of material of a body determine whether it will float or sink in water?
A metal cube of edge 5 cm and density 9 g cm-3 is suspended by a thread so as to be completely immersed in a liquid of density 1.2 g cm-3. Find the tension in thread. (Take g = 10 m s-2)
What is the unit of relative density?
Differentiate between density and relative density of a substance.
A solid weighs 1.5 kgf in air and 0.9 kgf in a liquid of density 1.2 × 103 kg m-3. Calculate R. D. of solid.
A body weighs 20 gf in air and 18.0 gf in water. Calculate the relative density of the material of the body.
A solid weighs 32 gf in air and 28.8 gf in water. Find: (i) The volume of solid, (ii) R.D. of solid and (iii) The weight of solid in a liquid of density 0.9 g cm-3.
An aluminium cube of side 5 cm and RD. 2.7 is suspended by a thread in alcohol of relative density 0.80. Find the tension in thread.
A cylinder made of copper and aluminium floats in mercury of density 13.6 gem-3, such that 0.26th part of it is below mercury. Find the density of solid.
