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A test tube loaded with lead shots weighs 25 gf and floats upto the mark X in water. When the test tube is made to float in brine solution

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प्रश्न

A test tube loaded with lead shots weighs 25 gf and floats upto the mark X in water. When the test tube is made to float in brine solution, it needs 5 gf more of lead shots to float upto level X. Find the relative density of brine solution.

योग
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उत्तर

When test tube floats is water:

Weight of test tube = 25 gf

By law of floatation

Weight of water displaced = Weight of test tube = 25 gf

When test tube floats in a brine solution, it needs 5 gf more of lead shots to float up to same level as in water.
Weight of test tube = 25 + 5 = 30 gf
By law of floatation :
Weight of brine solution displaced = Weight of test tube = 30 gf As, volume of brine solution displaced = Volume of water displaced

∴ R.D. of brine solution = `"Weight of brine solution displaced"/"Weight of water displaced"`

`= 30/25 = 1.2`

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Principle of Floatation (Laws of Flotation)
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Upthrust and Archimedes’ Principle - Subjective Questions

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गोयल ब्रदर्स प्रकाशन A New Approach to ICSE Physics [English] Class 9
अध्याय 5 Upthrust and Archimedes’ Principle
Subjective Questions | Q 12

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