Advertisements
Advertisements
Question
The relative density of mercury is 13.6. State its density in
(i) C.G.S. unit and
(ii) S.I. unit.
Advertisements
Solution 1
R.D. of mercury = 13.6
(i) Density in C.G.S. = 13.6 gcm-3
(ii) Density in S.I. = 13.6 × 103 kgm-3
Solution 2
Relative density = density of mercury /density of water.
The density of mercury = relative density X density of water.
Relative density = 13.6.
Density of water in C.G.S system = 1g cm-3.
So, density of mercury in C.G.S system = 13.6 X1 = 13.6 gcm-3.
The density of water in the SI system = 1000 Kg m-3.
So, density of mercury in SI system = 13.6 X1000 = 13.6 X103 Kgcm-3.
RELATED QUESTIONS
A solid of density 5000 kg m-3 weighs 0.5 kgf in air. It is completely immersed in water of density 1000 kg m-3. Calculate the apparent weight of the solid in water.
Differentiate between density and relative density of a substance.
A body of volume 100 cm3 weighs 1 kgf in air. Find:
- Its weight in water and
- Its relative density.
A body of mass 70 kg, when completely immersed in water, displaces 20,000 cm3 of water. Find: (i) The weight of body in water and (ii) The relative density of material of the body.
A solid of area of cross-section 0.004 m2 and length 0.60 m is completely immersed in water of density 1000 kgm3. Calculate:
- Wt of solid in SI system
- Upthrust acting on the solid in SI system.
- Apparent weight of solid in water.
- Apparent weight of solid in brine solution of density 1050 kgm3.
[Take g = 10 N/kg; Density of solid = 7200 kgm3]
A piece of metal weighs 44.5 gf in air, 39.5 gf in water. What is the R.D. of the metal?
A body of volume 100 cm3 weighs 1 kgf in air. Calculate its weight in water. What is its relative density?
