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प्रश्न
The relative density of mercury is 13.6. State its density in
(i) C.G.S. unit and
(ii) S.I. unit.
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उत्तर १
R.D. of mercury = 13.6
(i) Density in C.G.S. = 13.6 gcm-3
(ii) Density in S.I. = 13.6 × 103 kgm-3
उत्तर २
Relative density = density of mercury /density of water.
The density of mercury = relative density X density of water.
Relative density = 13.6.
Density of water in C.G.S system = 1g cm-3.
So, density of mercury in C.G.S system = 13.6 X1 = 13.6 gcm-3.
The density of water in the SI system = 1000 Kg m-3.
So, density of mercury in SI system = 13.6 X1000 = 13.6 X103 Kgcm-3.
संबंधित प्रश्न
Complete the following sentence.
Density in kg m-3 = ............ × density in g cm-3
The unit of relative density is :
Calculate the mass of a body whose volume is 2 m3 and relative density is 0.52.
A body weighs 20 gf in air and 18.0 gf in water. Calculate the relative density of the material of the body.
A piece of stone of mass 113 g sinks to the bottom in water contained in a measuring cylinder and water level in cylinder rises from 30 ml to 40 ml. Calculate R.D. of stone.
A body of mass 70 kg, when completely immersed in water, displaces 20,000 cm3 of water. Find: (i) The weight of body in water and (ii) The relative density of material of the body.
A stone of density 3000 kgm3 is lying submerged in water of density 1000 kgm3. If the mass of stone in air is 150 kg, calculate the force required to lift the stone. [g = 10 ms2]
A solid of R.D. 4.2 is found to weigh 0.200 kgf in air. Find its apparent weight in water.
An aluminium cube of side 5 cm and RD. 2.7 is suspended by a thread in alcohol of relative density 0.80. Find the tension in thread.
A piece of wax floats in brine. What fraction of its volume will be immersed?
R.D. of wax = 0.95, R.D. of brine = 1.1.
