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Question
A solid is in the form of a cylinder with hemispherical ends. Total height of the solid is 19 cm and the diameter of the cylinder is 7 cm. Find the volume and total surface area of the solid.
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Solution
Volume of cylinder = `pir^2 h`
`=22/7 xx 7/2 xx 7/2 xx 12`
`=462 xm^3`
Volume of 2 hemisphere = `4pir^3`
`=4/3 xx 22/7 xx 7/2 xx 7/2 xx 7/2`
`=179.6 cm^3`
Therefore,
Volume of solid `=462 + 179.6`
`=641.6 cm^3`
Total surface area of the solid
`=2pirh + 4pir^2`
`= 2pir (h +2r)`
`= 2 xx 22/7 xx 7/2 (12 + 2 xx 7/2)`
`= 418 cm^2`
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