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A Solid is in the Form of a Cylinder with Hemispherical Ends. Total Height of the Solid is 19 Cm and the Diameter of the Cylinder is 7 Cm. Find the Volume and Total Surface Area of the Solid.

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प्रश्न

A solid is in the form of a cylinder with hemispherical ends. Total height of the solid is 19 cm and the diameter of the cylinder is 7 cm. Find the volume and total surface area of the solid.

संक्षेप में उत्तर
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उत्तर

Volume of cylinder = `pir^2 h`

                             `=22/7 xx 7/2 xx 7/2 xx 12`

                             `=462 xm^3`

Volume of 2 hemisphere = `4pir^3`

                                       `=4/3 xx 22/7 xx 7/2 xx 7/2 xx 7/2`

                                       `=179.6 cm^3`

Therefore,

 Volume of solid `=462 + 179.6`

`=641.6 cm^3`

Total surface area of the solid

`=2pirh + 4pir^2`

`= 2pir (h +2r)`

`= 2 xx 22/7 xx 7/2 (12 + 2 xx 7/2)`

`= 418 cm^2`

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अध्याय 14: Surface Areas and Volumes - Exercise 14.3 [पृष्ठ ८४]

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आर.डी. शर्मा Mathematics [English] Class 10
अध्याय 14 Surface Areas and Volumes
Exercise 14.3 | Q 56 | पृष्ठ ८४

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