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Question
A circus tent is cylindrical to a height of 4 m and conical above it. If its diameter is 105 m and its slant height is 40 m, the total area of the canvas required in m2 is
Options
1760
2640
3960
7920
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Solution
For conical portion
` r = 52 .5m and l = 40m`
Curved surface area of the conical portion
`= pirl`
`=pi xx 52.5 xx 40`
`= 2100 pi m^2`
For cylindrical portion we have
r = 52.5m and h =4m
Then,
Curved surface area of cylindrical portion
`=2pirh`
`=2 xx pi xx 52.5 xx 4`
` = 420 pi m^2`
Area of canvas used for making the tent
`= (2100m + 420)pi`
`=2520 xx 22/7`
`= 7920m^2`
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