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A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube.

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Question

A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid.

Sum
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Solution

Diameter of hemisphere = Edge of cube = l

Radius of hemisphere = `l/2`

Curved surface area of hemisphere = 2πr2

= `2 xx pi xx l/2 xxl/2 xx (pi l^2)/2`

Base area of the hemisphare = πr2

= `pi (l/2)^2 = (pil^2)/4`

Surface area of the cube = `6 xx l^2 = 6l^2`

Surface area of the remaining solid = [Total surface area of cube + C.S.A. of hemispjere − base area of hemisphere]

 = `6l^2 + (pil^2)/2 − (pil^2)/2`

= `(24l^2 + 2pil^2 − pil^2)/4`

= `(24l^2 + pil^2)/4`

= `l^2/4 (24 + pi)` sq. units.

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Chapter 12: Surface Areas and Volumes - EXERCISE 12.1 [Page 166]

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NCERT Mathematics [English] Class 10
Chapter 12 Surface Areas and Volumes
EXERCISE 12.1 | Q 5. | Page 166

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