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Question
A shell is fired from a cannon with a velocity V at an angle θ with the horizontal direction. At the highest point in its path, it explodes into two pieces of equal masses. One of the pieces retraces its path to the cannon. The speed of the other piece immediately after the explosion is
Options
3V cos θ
2V cos θ
\[\frac{3}{2}\] V cos θ
V cos θ
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Solution
3V cos θ
The linear momentum is conserved in horizontal direction.
\[\therefore\] Initial momentum = Final momentum
\[\Rightarrow mv \cos \theta = - \frac{m}{2}v \cos \theta + \frac{m}{2}v'\]
\[ \Rightarrow v' = mv \cos \theta\]
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