Advertisements
Advertisements
Question
A meter scale is pivoted at its mid point and a 50 g mass suspended from the 20 cm mark. What mass balances the ruler when suspended from 65 cm mark?
Advertisements
Solution
Let mass 'm' be suspended from 65 cm mark so as to balance the metre scale.
In balanced condition.
sum of clockwise moments = sum of anticlockwise moments
50 x (50 - 20) = m x (65 - 50)
or, 50 x 30 = m x 15
or, m = `1500/15` = 100g
APPEARS IN
RELATED QUESTIONS
Define equilibrium.
What do you mean by an equilibrium of a body?
State the condition when a body is in static equilibrium.
State two condition for a body acted upon by several forces to be in equilibrium.
A uniform meter scale is in equilibrium as shown in the diagram :
(i) Calculate the weight of the meter scale.
(ii) Which of the following options is correct to keep the ruler in equilibrium when 40 gf wt is shifted to 0 cm mark ?
F is shifted towards 0 cm
or
F is shifted towards 100 cm
Give scientific reason for the following:
In a moving bus the standing passenger stands keeping both his legs apart.
What makes a balance faulty?
What is a couple?
Give an experiment to verify the principle of moments.
Mention any two conditions for the stability of a body?
