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Question
A meter scale is pivoted at its mid point and a 50 g mass suspended from the 20 cm mark. What mass balances the ruler when suspended from 65 cm mark?
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Solution
Let mass 'm' be suspended from 65 cm mark so as to balance the metre scale.
In balanced condition.
sum of clockwise moments = sum of anticlockwise moments
50 x (50 - 20) = m x (65 - 50)
or, 50 x 30 = m x 15
or, m = `1500/15` = 100g
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