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Question
A machine is set to deliver packets of a given weight. Ten samples of size five each were recorded. Below are given relevant data:
| Sample number | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| `bar"X"` | 15 | 17 | 15 | 18 | 17 | 14 | 18 | 15 | 1 | 16 |
| R | 7 | 7 | 4 | 9 | 8 | 7 | 12 | 4 | 11 | 5 |
Calculate the control limits for mean chart and the range chart and then comment on the state of control, (conversion factors for n = 5, A2 = 0.58, D3 = 0 and D4 = 2.115)
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Solution
| Sample number | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | Tota |
| Mean `(bar"X")` | 15 | 17 | 15 | 18 | 17 | 14 | 18 | 15 | 1 | 16 | `sum"X"` = 162 |
| Range (R) | 7 | 7 | 4 | 9 | 8 | 7 | 12 | 4 | 11 | 5 | `sum"R"` = 74 |
The control limits for `bar"X"` chart is
`\overset{==}{"X"} = (sum"X")/"No. of samples" = 162/10` = 16.2
`bar"R" = (sum"R")/"No. of samples" = 74/10` = 7.4
UCL = `\overset{==}{"X"} + "A"_2+ bar"R"`
= 16.2 + (0.58)(7.4)
= 16.2 + 4.292
= 20.492
= 20.49
CL = `\overset{=}{"X"}` = 16.2
LCL = `\overset{==}{"X"} - "A"_2 bar"R"`
= 16.2 – (0.58)(7.4)
= 16.2 – 4.292
= 11.908
= 11.91
The control limits for Range chart is
CL = `"D"_4bar"R"`
= (2.115)(7.4)
= 15.651
= 15.65
CL = `bar"R"` = 7.4
LCL = `"D"_3 bar"R"` = (0)(7.4) = 0
The above diagram shows all the three control lines with the data points plotted.
We see that all the points of the sample mean are within the control limits.
We now draw the R chart for the given data.
The above diagram shows all the three control lines with the sample range points plotted.
We observe that all the points are within the control limits.
Conclusion: From the above two plots of the sample mean `bar"X"` and sample range R, we conclude that the process is in control.
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RELATED QUESTIONS
Define Statistical Quality Control
Define chance cause
Define assignable cause
Define a control chart
Write the control limits for the mean chart
Write the control limits for the R chart
A quality control inspector has taken ten samples of size four packets each from a potato chips company. The contents of the sample are given below, Calculate the control limits for mean and range chart.
| Sample Number | Observations | |||
| 1 | 2 | 3 | 4 | |
| 1 | 12.5 | 12.3 | 12.6 | 12.7 |
| 2 | 12.8 | 12.4 | 12.4 | 12.8 |
| 3 | 12.1 | 12.6 | 12.5 | 12.4 |
| 4 | 12.2 | 12.6 | 12.5 | 12.3 |
| 5 | 12.4 | 12.5 | 12.5 | 12.5 |
| 6 | 12.3 | 12.4 | 12.6 | 12.6 |
| 7 | 12.6 | 12.7 | 12.5 | 12.8 |
| 8 | 12.4 | 12.3 | 12.6 | 12.5 |
| 9 | 12.6 | 12.5 | 12.3 | 12.6 |
| 10 | 12.1 | 12.7 | 12.5 | 12.8 |
(Given for n = 5, A2 = 0.58, D3 = 0 and D4 = 2.115)
Choose the correct alternative:
`bar"X"` chart is a
Choose the correct alternative:
The LCL for R chart is given by
The following are the sample means and I ranges for 10 samples, each of size 5. Calculate; the control limits for the mean chart and range chart and state whether the process is in control or not.
| Sample Number | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| Mean | 5.10 | 4.98 | 5.02 | 4.96 | 4.96 | 5.04 | 4.94 | 4.92 | 4.92 | 4.98 |
| Range | 0.3 | 0.4 | 0.2 | 0.4 | 0.1 | 0.1 | 0.8 | 0.5 | 0.3 | 0.5 |
