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Question
A long bar magnet has a pole strength of 10 Am. Find the magnetic field at a point on the axis of the magnet at a distance of 5 cm from the north pole of the magnet.
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Solution
Given:
Pole strength of the bar magnet, m = 10 Am
Distance of the point from the north pole of the bar magnet, r = 5 cm = 0.05 m
We know,
The magnetic field due to magnetic charge (B) is given by
`B = u_0/(4pi) = m/r^2`
= `(10^-7 xx 10) / (5 xx 10^-2)^2 = (10^-6)/(25 xx 10^-4)`
= `(10^-2)/25 = 4 xx 10^-4 "T"`
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