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When a dipole rotates from θ = 0° to θ = 90° in a uniform electric field, how does its potential energy change?

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Question

When a dipole rotates from θ = 0° to θ = 90° in a uniform electric field, how does its potential energy change?

Options

  • Decreases from -pE to zero

  • Increases from zero to +pE

  • Increases from -pE to zero

  • Remains constant at -pE

MCQ
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Solution

The potential energy of a dipole is U = -pE cos θ. At θ = 0°, U = -pE (minimum). At θ = 90°, U = -pE cos(90°) = 0. Therefore, as the dipole rotates from parallel (θ = 0°) to perpendicular (θ = 90°) to the field, its potential energy increases from -pE to zero.

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