हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

A Long Bar Magnet Has a Pole Strength of 10 Am. Find the Magnetic Field at a Point on the Axis of the Magnet at a Distance of 5 Cm from the North Pole of the Magnet.

Advertisements
Advertisements

प्रश्न

A long bar magnet has a pole strength of 10 Am. Find the magnetic field at a point on the axis of the magnet at a distance of 5 cm from the north pole of the magnet.

योग
Advertisements

उत्तर

Given:
Pole strength of the bar magnet, m = 10 Am
Distance of the point from the north pole of the bar magnet, r  = 5 cm = 0.05 m
We know,

The magnetic field due to magnetic charge (B) is given by 

`B = u_0/(4pi) = m/r^2`

 = `(10^-7 xx 10) / (5 xx 10^-2)^2 = (10^-6)/(25 xx 10^-4)`

= `(10^-2)/25 = 4 xx 10^-4  "T"`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 36: Permanent Magnets - Exercises [पृष्ठ २७७]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 36 Permanent Magnets
Exercises | Q 1 | पृष्ठ २७७

संबंधित प्रश्न

Deduce the expression for the torque acting on a dipole of dipole moment `vecp` in the presence of a uniform electric field `vecE`


Maximum torque acting on an electric dipole of moment  3×10-29  Cm in a uniform electric field E is 6 × 10-25 Nm. Find E.


An electric dipole of dipole moment `vecP` is placed in a uniform electric field `vecE` with its axis inclined to the field. Write an expression for the torque `vecT` experienced by the dipole in vector form. Show diagrammatically how the dipole should be kept in the electric field so that the torque acting on it is:

  1. maximum
  2. Zero

Derive the expression for the torque acting on an electric dipole, when it is held in a uniform electric field. identify the orientation of the dipole in the electric field, in which it attains a stable equilibrium.


If the solenoid is free to turn about the vertical direction and a uniform horizontal magnetic field of 0.25 T is applied, what is the magnitude of torque on the solenoid when its axis makes an angle of 30° with the direction of applied field?


Assertion: The poles of magnet can not be separated by breaking into two pieces.

Reason: The magnetic moment will be reduced to half when a magnet is broken into two equal pieces.


Magnetic dipole moment is a vector quantity directed from ______.

An electric dipole of dipole moment 2 × 10-8 C-m in a uniform electric field experiences a maximum torque of 6 × 10-4 N-m. The magnitude of the electric field is ______.


An electric dipole of length 2 cm is placed at an angle of 30° with an electric field 2 × 105 N/C. If the dipole experiences a torque of 8 × 10-3 Nm, the magnitude of either charge of the dipole is ______.


When an electric dipole is placed in a uniform electric field, what is the net force acting on the dipole?


Derive the magnitude of torque acting on an electric dipole in a uniform electric field. Which of the following correctly represents this torque?


In vector form, how is the torque on an electric dipole in a uniform electric field expressed?


When the dipole moment is parallel to the electric field (θ = 0°), what is the magnitude of torque?


Which equilibrium position of a dipole in a uniform electric field is stable?


What is the potential energy of a dipole in unstable equilibrium in a uniform electric field?


What distinguishes the behavior of a dipole in a non-uniform electric field from its behavior in a uniform field?


What real-world phenomenon demonstrates the behavior of a dipole in a non-uniform electric field?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×