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A glass flask has a volume 1 × 10−4 m3. It is filled with a liquid at 30°C. If the temperature of the system is raised to 100°C, how much of the liquid will overflow? (Coefficient of volume expansion

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Question

A glass flask has a volume 1 × 10−4 m3. It is filled with a liquid at 30°C. If the temperature of the system is raised to 100°C, how much of the liquid will overflow? (Coefficient of volume expansion of glass is 1.2 × 105 (°C)1 while that of the liquid is 75 × 105 (°C)1).

Numerical
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Solution

Given: V1 = 1 × 10−4 m3 = 10−4 m3, T1 = 30°C, T2 = 100°C, γglass = 1.2 × 105 , `γ_"liquid"` = 75 × 105

To find: Volume of liquid that overflows

Formula: `gamma = (V_2 - V_1)/(V_1(T_2 - T_1))`

Calculation: From formula,

Increase in volume = V2 − V= γ = V1(T2 − T1)

Increase in volume of glass 

= γglass = V1(T2 − T1)

= 1.2 × 10−5 × 10−4 × (100 − 30)

= 1.2 × 70 × 10−9

= 8.4 × 10−8 m3

∴ Increase in volume of glass = 8.4 × 10−8 m

Increase in volume of liquid -

= `γ_"liquid"`= V1(T2 − T1)

= 75 × 10−5 × 10-4 × (100 − 30)

= 75 × 70 × 10−9

= 5250 × 10−9 m3

∴ Increase in volume of liquid = 5250 × 10−9 m3

∴ Volume of liquid which overflows

= (5250 − 84) × 10−9 m3

= 5166 × 10−9 m3

= 0.5166 × 10−8 m3

∴ Volume of liquid that overflows is 0.5166 × 10−8 m3

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Chapter 7: Thermal Properties of Matter - Exercises [Page 140]

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Balbharati Physics [English] Standard 11 Maharashtra State Board
Chapter 7 Thermal Properties of Matter
Exercises | Q 3. (i) | Page 140

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