English
Karnataka Board PUCPUC Science 2nd PUC Class 12

A first order reaction is 50% completed in 1.26 × 1014 s. How much time would it take for 100% completion? - Chemistry

Advertisements
Advertisements

Question

A first order reaction is 50% completed in 1.26 × 1014 s. How much time would it take for 100% completion?

Options

  • 1.26 × 1015 s

  • 2.52 × 1014 s

  • 2.52 × 1028 s

  • infinite

MCQ
Advertisements

Solution

infinite

Explanation:

Reaction would be 100% complete only after infinite time which cannot be calculated.

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Chemical Kinetics - Exercises [Page 51]

APPEARS IN

NCERT Exemplar Chemistry [English] Class 12
Chapter 4 Chemical Kinetics
Exercises | Q I. 16. | Page 51

RELATED QUESTIONS

Time required to decompose SO2Cl2 to half of its initial amount is 60 minutes. If the decomposition is a first order reaction, calculate the rate constant of the reaction.


The following data were obtained during the first order thermal decomposition of SO2Cl2 at a constant volume.

\[\ce{SO2Cl2_{(g)} -> SO2_{(g)} + Cl2_{(g)}}\]

Experiment Time/s–1 Total pressure/atm
1 0 0.5
2 100 0.6

Calculate the rate of the reaction when total pressure is 0.65 atm.


The rate constant for a first order reaction is 60 s−1. How much time will it take to reduce the initial concentration of the reactant to its `1/16`th value?


Define order of reaction. How does order of a reaction differ from molecularity for a complex reaction? 


Straight line graph for first order reaction is obtained between ____________.


Which of the following graphs is correct for a first order reaction?


State a condition under which a bimolecular reaction is kinetically first order reaction.


With the help of an example explain what is meant by pseudo first order reaction.


Time required to decompose SO2Cl2 to half of its initial concentration is 60 minutes. If the de-composite is a first order reaction, calculated the rate constant of the reaction-


Observe the graph shown in figure and answer the following questions:

  1. What is the order of the reaction?
  2. What is the slope of the curve?
  3. Write the relationship between k and t1/2 (half life period).

The decomposition of formic acid on gold surface follows first-order kinetics. If the rate constant at 300 K is 1.0 × 10−3 s−1 and the activation energy Ea = 11.488 kJ mol−1, the rate constant at 200 K is ______ × 10−5 s−1. (Round off to the Nearest Integer)

(Given R = 8.314 J mol−1 K−1)


What is the rate constant?


Slove: \[\ce{2NOBr -> 2NO_{2(g)} + Br_{2(g)}}\]

For the above reaction, the rate law is rate = k[NOBr]2. If the rate of reaction is 6.5 × 10−6 mol L−1 s−1 at 2 × 10−3 mol L−1 concentration of NOBr, calculate the rate constant k for the reaction.


The rate constant for the reaction:

\[\ce{2N2O_{(s)} ->2N2O4_{(g)}}\] is 4.98 × 10-4 s-1.

The order of the reaction is ______.


Write the equation for integrated rate law for a first order reaction.


Show that `t_(1/2)= 0.693/k` for first reaction.


Write the unit of rate constant [k] for the first order reaction.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×