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Question
A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle?
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Solution
Let the food last for x days. According to question,
| Number of days | 6 | x |
| Number of animals | 20 | 30 |
Since the given problem is in inverse proportion.
∴ 6 × 20 = x × 30
⇒ `(6xx20)/30` = x
⇒ 4 = x
Therefore, the required number of days is 4.
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