Advertisements
Advertisements
प्रश्न
A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle?
Advertisements
उत्तर
Let the food last for x days. According to question,
| Number of days | 6 | x |
| Number of animals | 20 | 30 |
Since the given problem is in inverse proportion.
∴ 6 × 20 = x × 30
⇒ `(6xx20)/30` = x
⇒ 4 = x
Therefore, the required number of days is 4.
APPEARS IN
संबंधित प्रश्न
A school has 8 periods a day each of 45 minutes duration. How long would each period be, if the school has 9 periods a day, assuming the number of school hours to be the same?
A work-force of 420 men with a contractor can finish a certain piece of work in 9 months. How many extra men must he employ to complete the job in 7 months?
6 pipes are required to fill a tank in 1 hour 20 minutes. How long will it take if only 5 pipes of the same type are used?
A printer, prints a book of 300 pages at the rate of 30 pages per minute. Then, how long will it take to print the same book if the speed of the printer is 25 pages per minute?
Six men can complete a work in 12 days. Two days later, 6 more men joined them. How many days will they take to complete the remaining work?
If xy = 10, then x and y vary ______ with each other.
If a tree 24 m high casts a shadow of 15 m, then the height of a pole that casts a shadow of 6 m under similar conditions is 9.6 m.
If x and y are in inverse proportion, then (x + 1) and (y + 1) are also in inverse proportion.
Write whether the following statement vary directly, vary inversely with each other, or neither of the two.
The number of people working and the time to complete a given work.
If x varies inversely as y and x = 20 when y = 600, find y when x = 400.
