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Question
A die is thrown once. Find the probability of getting an even number.
Sum
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Solution
In a single throw of a die, the possible outcomes are 1, 2, 3, 4, 5 and 6.
Total number of possible outcomes = 6.
Let E be the event of getting an even number.
Then, the favourable outcomes are 2, 4 and 6.
Number of favourable outcomes = 3.
∴ Probability of getting an even number
P(E) = `"Number of favourable outcome"/"Total number of possible outcomes"`
= `3/6`
= `1/2`
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