Question

A die is thrown once. Find the probability of getting a number less than 5.

Answer 1

In a single throw of a die, the possible outcomes are 1, 2, 3, 4, 5 and 6.

Total number of possible outcomes = 6

Let E be the event of getting a number less than 5.

Then, the favourable outcomes are 1, 2, 3, 4

Number of favourable outcomes = 4

∴ Probability of getting a number less than 5 =  P(E) = `"Number of favourable outcome"/"Total number of possible outcomes"=4/6 = 2/3`