English
Tamil Nadu Board of Secondary EducationHSC Science Class 11

A certain number of spherical drops of a liquid of radius R coalesce to form a single drop of radius R and volume V. If T is the surface tension of the liquid, then

Advertisements
Advertisements

Question

A certain number of spherical drops of a liquid of radius R coalesce to form a single drop of radius R and volume V. If T is the surface tension of the liquid, then

Options

  • energy = `4 "VT" (1/"r" - 1/"R")` is released

  • energy = `3 "VT" (1/"r" + 1/"R")` is absorbed

  • energy = `3 "VT" (1/"r" - 1/"R")` is released

  • energy is neither released nor absorbed

MCQ
Advertisements

Solution

energy = `3 "VT" (1/"r" - 1/"R")` is released

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Properties of Matter - Evaluation [Page 91]

APPEARS IN

Samacheer Kalvi Physics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 7 Properties of Matter
Evaluation | Q I. 12. | Page 91

RELATED QUESTIONS

'n' droplets of equal size of radius r coalesce to form a bigger drop of radius R. The energy liberated is equal to...................

(T =Surface tension of water)

`(a) 4piR^2T[n^(1/3)-1]`

`(b) 4pir^2T[n^(1/3)-1]`

`(c) 4piR^2T[n^(2/3)-1]`

`(d)4 pir^2T[n^(2/3)-1]`


Figure  (a) shows a thin liquid film supporting a small weight = 4.5 × 10–2 N. What is the weight supported by a film of the same liquid at the same temperature in Fig. (b) and (c)? Explain your answer physically.


The total free surface energy of a liquid drop is `pisqrt2` times the surface tension of the liquid. Calculate the diameter of the drop in S.l. unit.


When a sparingly soluble substance like alcohol is dissolved in water, surface tension of water


The rise of a liquid in a capillary tube depends on

(a) the material
(b) the length
(c) the outer radius
(d) the inner radius of the tube


Find the excess pressure inside (a) a drop of mercury of radius 2 mm (b) a soap bubble of radius 4 mm and (c) an air bubble of radius 4 mm formed inside a tank of water. Surface tension of mercury, soap solution and water are 0.465 N m−1, 0.03 N m−1 and 0.076 N m−1 respectively.


The lower end of a capillary tube of radius 1 mm is dipped vertically into mercury. (a) Find the depression of mercury column in the capillary. (b) If the length dipped inside is half the answer of part (a), find the angle made by the mercury surface at the end of the capillary with the vertical. Surface tension of mercury = 0.465 N m−1 and the contact angle of mercury with glass −135 °.


How does the friction arise between the surfaces of two bodies in relative motion?


Why is raindrop spherical in nature?


The length of a needle floating on water is 2 cm. The additional force due to surface tension required to pull the needle out of water will be (S.T. of water = 7.0 × 10−2 N/m). 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×