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प्रश्न
A certain number of spherical drops of a liquid of radius R coalesce to form a single drop of radius R and volume V. If T is the surface tension of the liquid, then
पर्याय
energy = `4 "VT" (1/"r" - 1/"R")` is released
energy = `3 "VT" (1/"r" + 1/"R")` is absorbed
energy = `3 "VT" (1/"r" - 1/"R")` is released
energy is neither released nor absorbed
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उत्तर
energy = `3 "VT" (1/"r" - 1/"R")` is released
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संबंधित प्रश्न
'n' droplets of equal size of radius r coalesce to form a bigger drop of radius R. The energy liberated is equal to...................
(T =Surface tension of water)
`(a) 4piR^2T[n^(1/3)-1]`
`(b) 4pir^2T[n^(1/3)-1]`
`(c) 4piR^2T[n^(2/3)-1]`
`(d)4 pir^2T[n^(2/3)-1]`
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