English

A Building Worth Rs 1, 33,100 is Constructed on a Plot of Land Worth Rs 72,900. After How Many Years Will the Values of Both Be Same, - Mathematics

Advertisements
Advertisements

Question

A building worth Rs 1, 33,100 is constructed on a plot of land worth Rs 72,900. After how many years will the values of both be same, if the land appreciates at 10% p.a. and the building depreciates at 10% p.a.?

Sum
Advertisements

Solution

For the building: 

`"V"_"n" = "V"_0  (1 - "r"/100)^"n"`

Vn = Rs 133100 `(1 - 10/100)^"n"`

V= Rs 133,100 x (0. 9)n

For the plot :

`"V"_"n" = "V"_0  (1 + "r"/100)^"n"`

Vn = Rs 72900 `(1 + 10/100)^"n"`

Vn = Rs 72900 × (1.1)n

Since, value becomes same: 

1,33,100 x (0.9)n = 72, 900 x (1.1)n `lim_(x -> ∞)`

`(1.1)^"n"/(0.9)^"n" = 133100/72900`

`(1.1)^"n"/(0.9)^"n" = 1331 /729 = 11^3/9^3`

t = 3

Hence, after 3 years value of both will be same. 

shaalaa.com
Finding CI from the Relation CI = A – P
  Is there an error in this question or solution?
Chapter 1: Compound Interest - Exercise 1.7 [Page 26]

APPEARS IN

Frank Mathematics - Part 2 [English] Class 10 ICSE
Chapter 1 Compound Interest
Exercise 1.7 | Q 12 | Page 26

RELATED QUESTIONS

Find the difference between the compound interest and the simple interest in 3 years on Rs 15,000 at 8% p.a. compounded yearly.


Meera borrowed Rs 35,000 at 12.5% p.a. simple interest for 3 years. She immediately gave it to Archana at 12 % p.a. compound interest compounded annually. Find Meera's loss or gain at the end of 3 years.


Calculate the amount and the compound interest for the following, when cornpounded half-yearly: 

Rs 6,000 for `1 1/2` years at 10 % p.a. 


Calculate the amount and the compound interest for the following: 

Rs 20,000 for 2 years if the rates of interest are `12 1/4` and `5 1/2` for the successive years.


On what sum will the difference between compound interest and the simple interest for 3 years at 12% be Rs 1,123.20?


The population of a village increases at the rate of 50 per thousand. Its population after 2 years will be 22,050. Find the present population.


The present population of a town is 1, 15200.If it increases at the rate of `6 2/3`% per annum , find

Its population after 2 years 


A machine was purchased 2 years ago. Its value decreases by 10% every year. Its present value is Rs 19,083.60. For how much money was the machine purchased?


The cost of a T.V. was quoted Rs 17,000 at the beginning of the year 1999. In the beginning of 2000 the price was hiked by 5%. Because of decrease in demand the cost was reduced by 4% in the beginning of 2001. What is the cost of the T.V. in 2001?


Find the difference between the simple interest and compound interest on 2,500 for 2 years at 4% p.a., compound interest being reckoned semi-annualy.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×