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Find the Difference Betlween the Compound Interest Compounded Yearly and Half-yearly for the Following: - Mathematics

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Question

Find the difference betlween the compound interest compounded yearly and half-yearly for the following: 

Rs 15,000 for `1 1/2` years at 12 % p.a.

Sum
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Solution

P=Rs 15,000 ;  t = `1 1/2` years

When compounded yearly : r = 12 % p.a. 

`"A" = "P" (1 + "r"/100)^"n"`

A = Rs `15000 (1 + 12/100)(1 + 12/100)^(1/2)`

= Rs 15000 x 1.12 x `(1 + 1/2 xx 12/100)` 

= Rs15,000 x 1.12 x 1.06

= Rs 17,808 

C.l. = A - P

= Rs (17,808 -15,000)

= Rs 2808

When compounded half-yearly :

`"A" = "P" (1 + "r"/100)^"n"`

A = Rs 15000 `(1 + 6/100)^3`

= Rs 15,000 x 1.06 x 1.06 x 1.06

= Rs 17,865.24 

C.l. = A - P

= Rs (17,865.24 - 15,000)

= Rs2,865.24 

Hence the difference in the interest=Rs (2,865.24 - 2,808) =Rs 57.24 

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Finding CI from the Relation CI = A – P
  Is there an error in this question or solution?
Chapter 1: Compound Interest - Exercise 1.6 [Page 20]

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Frank Mathematics - Part 2 [English] Class 10 ICSE
Chapter 1 Compound Interest
Exercise 1.6 | Q 4.1 | Page 20

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