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Find the Difference Betlween the Compound Interest Compounded Yearly and Half-yearly for the Following: - Mathematics

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प्रश्न

Find the difference betlween the compound interest compounded yearly and half-yearly for the following: 

Rs 15,000 for `1 1/2` years at 12 % p.a.

योग
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उत्तर

P=Rs 15,000 ;  t = `1 1/2` years

When compounded yearly : r = 12 % p.a. 

`"A" = "P" (1 + "r"/100)^"n"`

A = Rs `15000 (1 + 12/100)(1 + 12/100)^(1/2)`

= Rs 15000 x 1.12 x `(1 + 1/2 xx 12/100)` 

= Rs15,000 x 1.12 x 1.06

= Rs 17,808 

C.l. = A - P

= Rs (17,808 -15,000)

= Rs 2808

When compounded half-yearly :

`"A" = "P" (1 + "r"/100)^"n"`

A = Rs 15000 `(1 + 6/100)^3`

= Rs 15,000 x 1.06 x 1.06 x 1.06

= Rs 17,865.24 

C.l. = A - P

= Rs (17,865.24 - 15,000)

= Rs2,865.24 

Hence the difference in the interest=Rs (2,865.24 - 2,808) =Rs 57.24 

shaalaa.com
Finding CI from the Relation CI = A – P
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Compound Interest - Exercise 1.6 [पृष्ठ २०]

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फ्रैंक Mathematics - Part 2 [English] Class 10 ICSE
अध्याय 1 Compound Interest
Exercise 1.6 | Q 4.1 | पृष्ठ २०

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