Advertisements
Advertisements
Question
The present population of a town is 1, 15200.If it increases at the rate of `6 2/3`% per annum , find
Its population after 2 years
Advertisements
Solution
Vn = 7 ' Vo= 115200 ; r = `6 2/3` % = 20/3 % ; t = 2 years
`"V"_"n" = "V"_0 xx (1 + "r"/100)`
`"V"_"n" = 115200 (1 + 20/(100 xx 3))^2`
`"V"_"n" 1,15, 200 xx 1.06667 xx 1.06667 `
Vn= 1,31,072
The population 2 years later= 1, 31,072
RELATED QUESTIONS
The simple interest and the compound interest on a certain sum of money for 2 years at the same rate of interest are Rs 8,000 and Rs 8,640 respectively. Calculate the rate of interest and the sum.
Find the difference between the compound interest and the simple interest in 3 years on Rs 15,000 at 8% p.a. compounded yearly.
Anand borrows Rs 20,000at 9 % p.a. simple interest for 3 years. He immediately gave it to Prakash at `8 1/2 %` p.a. compound interest compounded annually.
Find Anand's loss or gain.
Calculate the Amount and Cornpound Interest for the Following, when Cornpounded Annually:
Rs 12,000 for 3 years at 15 % p.a.
The population of a town in the year 2005 was 4, 25,000. Find its population in the year 2007 if the rate of annual increase is 4% per year.
The population of a village increases at the rate of 50 per thousand. Its population after 2 years will be 22,050. Find the present population.
In a factory the production of scooters rose to 46,305 from 40,000 in 3 years. Find the annual rate of growth of the production of scooters.
A machine was purchased 2 years ago. Its value decreases by 10% every year. Its present value is Rs 19,083.60. For how much money was the machine purchased?
A building worth Rs 1, 33,100 is constructed on a plot of land worth Rs 72,900. After how many years will the values of both be same, if the land appreciates at 10% p.a. and the building depreciates at 10% p.a.?
Find the difference between the simple interest and compound interest on 2,500 for 2 years at 4% p.a., compound interest being reckoned semi-annualy.
