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Question
The present population of a town is 1,
0/o per annum 1, 15,200. If it increases at the rate of `6 2/3` % per annum find
Its population 2 years ago.
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Solution
Vn = ? ; V0 = 115200 ; r = `6 2/3` % = `20/3` % ; t = 2 years
`"V"_"n" = "V"_0 (1 + "r"/100)^"n"`
`"V"_"n" = 115200 (1 - 20/(100 xx 3))^2`
`"V"_"n" = 1, 15, 200 xx 0.933333 xx 0.933333`
Vn = 1,00,352
The population 2 years ago was = 1, 00,352
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