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The Present Population of a Town is 1, 15,200. If It Increases at the Rate of 6 2 3 0/O per Annum 1 Find Its Population 2 Years Ago. - Mathematics

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प्रश्न

The present population of a town is 1, 
0/o per annum 1, 15,200. If it increases at the rate of `6 2/3` % per annum find  
Its population 2 years ago.

योग
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उत्तर

Vn = ? ; V0 = 115200 ; r = `6 2/3` % = `20/3` % ; t = 2 years

`"V"_"n" = "V"_0  (1 + "r"/100)^"n"`

`"V"_"n" = 115200 (1 - 20/(100 xx 3))^2`

`"V"_"n" = 1, 15, 200 xx 0.933333 xx 0.933333`

Vn = 1,00,352 

The population 2 years ago was = 1, 00,352 

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Finding CI from the Relation CI = A – P
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अध्याय 1: Compound Interest - Exercise 1.7 [पृष्ठ २५]

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फ्रैंक Mathematics - Part 2 [English] Class 10 ICSE
अध्याय 1 Compound Interest
Exercise 1.7 | Q 5.2 | पृष्ठ २५

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