Advertisements
Advertisements
Question
The population of a town in the year 2005 was 4, 25,000. Find its population in the year 2007 if the rate of annual increase is 4% per year.
Advertisements
Solution
vn =? ; v0 = 4,25,000 ; r = 4 % ; t = 2 years
Vn = V0 `(1 + "r"/100)^"t"`
Vn = 425000 `(1 + 4/100)^2`
Vn = 4,25,000 x 1.04 x 1.04
Vn = 4,59,680
The population in 2007 is 4,59,680
RELATED QUESTIONS
Find the difference between the compound interest and the simple interest in 3 years on Rs 15,000 at 8% p.a. compounded yearly.
Anand borrows Rs 20,000at 9 % p.a. simple interest for 3 years. He immediately gave it to Prakash at `8 1/2 %` p.a. compound interest compounded annually.
Find Anand's loss or gain.
Calculate the Amount and Cornpound Interest for the Following, when Cornpounded Annually:
Rs 12,000 for 3 years at 15 % p.a.
On what sum will the difference between compound interest and the simple interest for 2 years at `7 1/2` % be Rs 22.50 ?
On what sum will the difference between compound interest and the simple interest for 3 years at 12% be Rs 1,123.20?
The population of a city is 1, 25,000. If the annual birth rate and death rate are 5.5% and 3.5% respectively, calculate the population of the city after 3 years.
The population of a village increases at the rate of 50 per thousand. Its population after 2 years will be 22,050. Find the present population.
In a factory the production of scooters rose to 46,305 from 40,000 in 3 years. Find the annual rate of growth of the production of scooters.
A machine was purchased 2 years ago. Its value decreases by 10% every year. Its present value is Rs 19,083.60. For how much money was the machine purchased?
A building worth Rs 1, 33,100 is constructed on a plot of land worth Rs 72,900. After how many years will the values of both be same, if the land appreciates at 10% p.a. and the building depreciates at 10% p.a.?
