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Find the Difference Between the Compound Interest Compounded Yearly and Half-yearly for the Following: - Mathematics

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Question

Find the difference between the compound interest compounded yearly and half-yearly for the following: 

Rs 20,000 for `1 1/2` years at 16 %  p.a.

Sum
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Solution

P=Rs 20,000;  t = `1 1/2` years 

When compounded yearly: r = 16% p.a.

`"A" = "P" (1 + "r"/100)^"n"`

A = Rs 20000 `(1 + 16/100)(1 + 16/100)^(1/2)`

= Rs 20000 × 1.16 × `(1 + 1/2 xx 16/100)`

= Rs 20, 000 x 1.16 x 1.08

= Rs 25,056 
C.I. = A - P

= Rs (25,056 - 20,000)

= Rs 5,056 

When compounded half-yearly: 

`"A" = "P" (1 + "r"/100)^"n"`

A = Rs 20000 `(1 + 8/100)^3`

= Rs 20,000 x 1.08 x 1.08 x 1.08

= Rs 25,194.24 

C.l. = A - P

= Rs (25,194.24- 20,000)

= Rs 5,194.24 

Hence the difference in the interest=Rs (5,194.24 - 5,056) = Rs 138.24 

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Finding CI from the Relation CI = A – P
  Is there an error in this question or solution?
Chapter 1: Compound Interest - Exercise 1.6 [Page 20]

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Frank Mathematics - Part 2 [English] Class 10 ICSE
Chapter 1 Compound Interest
Exercise 1.6 | Q 4.2 | Page 20

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