Advertisements
Advertisements
Question
The population of a village increases at the rate of 50 per thousand. Its population after 2 years will be 22,050. Find the present population.
Advertisements
Solution
Rate of increase =
r = `50/1000 xx 100` = 5 %
Vn =22,050 ; V0 = ? ; r = 5 % ; t = 2 years
Vn = V0 `(1 + "r"/100)^"t"`
22050 = V0 `(1 + 5/100)^2`
22, 050 = v. × 1.05 × 1.05
V0 = `22050/11025`
V0 = 20000
The present population is 20,000.
RELATED QUESTIONS
The simple interest on a certain sum in 2 years is Rs 1,300, whereas the compound interest on the same sum at the same rate and for the same time is Rs 1,365. Find the rate per cent and the sum.
Find the difference between the compound interest and the simple interest in 3 years on Rs 15,000 at 8% p.a. compounded yearly.
Calculate the Amount and Cornpound Interest for the Following, when Cornpounded Annually:
Rs 12,000 for 3 years at 15 % p.a.
Calculate the amount and the compound interest for the following:
Rs 20,000 for 2 years if the rates of interest are `12 1/4` and `5 1/2` for the successive years.
On what sum will the difference between compound interest and the simple interest for 2 years at `7 1/2` % be Rs 22.50 ?
The population of a town in the year 2005 was 4, 25,000. Find its population in the year 2007 if the rate of annual increase is 4% per year.
In a factory the production of scooters rose to 46,305 from 40,000 in 3 years. Find the annual rate of growth of the production of scooters.
The present population of a town is 1,
0/o per annum 1, 15,200. If it increases at the rate of `6 2/3` % per annum find
Its population 2 years ago.
The value of the refrigerator which was purchased 2 years ago, depreciates at 12% per annum. If its present value is Rs 9,680. For how much was it purchased?
A building worth Rs 1, 33,100 is constructed on a plot of land worth Rs 72,900. After how many years will the values of both be same, if the land appreciates at 10% p.a. and the building depreciates at 10% p.a.?
