Advertisements
Advertisements
प्रश्न
The present population of a town is 1, 15200.If it increases at the rate of `6 2/3`% per annum , find
Its population after 2 years
Advertisements
उत्तर
Vn = 7 ' Vo= 115200 ; r = `6 2/3` % = 20/3 % ; t = 2 years
`"V"_"n" = "V"_0 xx (1 + "r"/100)`
`"V"_"n" = 115200 (1 + 20/(100 xx 3))^2`
`"V"_"n" 1,15, 200 xx 1.06667 xx 1.06667 `
Vn= 1,31,072
The population 2 years later= 1, 31,072
APPEARS IN
संबंधित प्रश्न
The simple interest on a certain sum in 2 years is Rs 1,300, whereas the compound interest on the same sum at the same rate and for the same time is Rs 1,365. Find the rate per cent and the sum.
Calculate the amount and the compound interest for the following:
Rs 20,000 for 2 years if the rates of interest are `12 1/4` and `5 1/2` for the successive years.
Find the difference betlween the compound interest compounded yearly and half-yearly for the following:
Rs 15,000 for `1 1/2` years at 12 % p.a.
On what sum will the difference between compound interest and the simple interest for 3 years at 12% be Rs 1,123.20?
The population of a town in the year 2005 was 4, 25,000. Find its population in the year 2007 if the rate of annual increase is 4% per year.
The population of a city is 1, 25,000. If the annual birth rate and death rate are 5.5% and 3.5% respectively, calculate the population of the city after 3 years.
Under the electrification programme of villages, the number of villages with electricity rose to 27,040 from 25,000 in 2 years. Find the rate of growth in the number of villages with electricity.
The value of a property decreases every year at the rate of 5%. If its value at the end of 3 years be Rs 44,540, what was the original value at the beginning of these 3 years?
A building worth Rs 1, 33,100 is constructed on a plot of land worth Rs 72,900. After how many years will the values of both be same, if the land appreciates at 10% p.a. and the building depreciates at 10% p.a.?
Find the Compound Interest on Rs. 2,000 for 3 years at 15% per annum Compounded annually.
