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The Present Population of a Town is 1,15,200. If It Increases at the Rate of 6 2 0/O per Annum 1 Find Its Population After 2 Years - Mathematics

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प्रश्न

The present population of a town is 1, 15200.If it increases at the rate of `6 2/3`% per annum , find

Its population after 2 years 

योग
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उत्तर

Vn = 7 ' Vo= 115200 ; r = `6 2/3` % = 20/3 % ; t = 2 years

`"V"_"n" = "V"_0 xx (1 + "r"/100)`

`"V"_"n" = 115200 (1 + 20/(100 xx 3))^2`

`"V"_"n" 1,15, 200 xx 1.06667 xx 1.06667 `

Vn= 1,31,072 

The population 2 years later= 1, 31,072 

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अध्याय 1: Compound Interest - Exercise 1.7 [पृष्ठ २५]

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फ्रैंक Mathematics - Part 2 [English] Class 10 ICSE
अध्याय 1 Compound Interest
Exercise 1.7 | Q 5.1 | पृष्ठ २५

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