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Question
A bag contains 3 red balls, 5 black balls and 4 white balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is:
not red?
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Solution
\[\text{ Number of red balls } = 3\]
\[\text{ Number of black balls } = 5 \]
\[\text{ Number of white balls } = 4\]
\[\text{ Total number of balls }= 3 + 5 + 4 = 12\]
\[\text{ Therefore, the total number of cases is 12 } . \]
\[P\left( \text{ not a red ball } \right) = 1 - P\left( \text{ a red ball }\right) = 1 - \frac{1}{4} = \frac{3}{4}\]
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