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Question
In a simultaneou throw of a pair of dice, find the probability of getting:
an even number on first
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Solution
\[\text{ When a pair of dice is thrown simultaneously, the sample space will be as follow }: \]
\[S = \left\{ \left( 1, 1 \right), \left( 1, 2 \right), \left( 1, 3 \right), \left( 1, 4 \right), \cdots\left( 6, 5 \right), \left( 6, 6 \right) \right\}\]
\[\text{ Hence, the total number of outcomes is 36 }. \]
\[\text{ Let A be the event of getting pairs who has even numbers on first in the sample space }. \]
\[\text{ The pairs who has even numbers on first are }: \left( 2, 1 \right), \left( 2, 2 \right), \ldots\left( 2, 6 \right), \left( 4, 1 \right), \cdots, \left( 4, 6 \right), \left( 6, 1 \right), \cdots\left( 6, 6 \right) . \]
\[\text{ Hence, the number of favourable outcomes is 18 }. \]
\[ \therefore P\left( A \right) = \frac{\text{ Number of favourable outcomes }}{\text{ Total number of outcomes }} = \frac{18}{36} = \frac{1}{3}\]
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