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Question
A 10 V battery of negligible internal resistance is connected across a 200 V battery and a resistance of 38Ω as shown in the figure. Find the value of the current in circuit.
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Solution
Since, the positive terminal of the batteries are connected together, so the equivalent emf of the batteries is given by ε = 200 - 10 = 190 V.
Hence, the current in the circuit is given by `I = ε /R = 190/38 = 5 A .`
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