Advertisements
Advertisements
Question
How is the net electric field related to the external field and the induced opposing field in a dielectric?
Options
\[E=E_PE_0\]
\[E=E_0+E_P\]
\[E=E_0-E_P\]
\[E=\frac{E_P}{E_0}\]
MCQ
Advertisements
Solution
The induced field \[E_P\] opposes the external field \[E_0\]. Therefore, the net field inside the dielectric is reduced and is given by \[E=E_0-E_P\].
shaalaa.com
Is there an error in this question or solution?
