Question

How is the net electric field related to the external field and the induced opposing field in a dielectric?

विकल्प

• \[E=E_PE_0\]

• \[E=E_0+E_P\]

• \[E=E_0-E_P\]

• \[E=\frac{E_P}{E_0}\]

Answer 1

The induced field \[E_P\] opposes the external field \[E_0\]. Therefore, the net field inside the dielectric is reduced and is given by \[E=E_0-E_P\].