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प्रश्न
How is the net electric field related to the external field and the induced opposing field in a dielectric?
पर्याय
\[E=E_PE_0\]
\[E=E_0+E_P\]
\[E=E_0-E_P\]
\[E=\frac{E_P}{E_0}\]
MCQ
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उत्तर
The induced field \[E_P\] opposes the external field \[E_0\]. Therefore, the net field inside the dielectric is reduced and is given by \[E=E_0-E_P\].
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