Advertisements
Advertisements
Question
`[(3/7)^-3]^4` = ______
Options
`(3/7)^-7`
`(3/7)^-10`
`(7/3)^12`
`(3/7)^20`
Advertisements
Solution
`[(3/7)^-3]^4 = bbunderline((7/3)^12)`
Explanation:
`[(3/7)^-3]^4 = (3/7)^(-3(4))` ...[∵ (am)n = amn]
`= (3/7)^-12`
`= (7/3)^12` ....`[∵ (a)^-"n" = 1/"a"^"n"]`
RELATED QUESTIONS
Evaluate:
`7^0 xx (25)^(-3/2) - 5^(-3)`
Simplify :
`( 8x^3 ÷ 125y^3 )^(2/3)`
Simplify:
`[ 5^( n + 3 ) - 6 xx 5^( n + 1 )]/[ 9 xx 5^n - 5^n xx 2^2 ]`
Simplify :
`( 3x^2 )^(-3) xx ( x^9 )^(2/3)`
Evaluate :
`sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3)`
Evaluate:
`(27/8)^(2/3) - (1/4)^-2 + 5^0`
Simplify the following and express with a positive index:
`(32)^(-2/5) ÷ (125)^(-2/3)`
Simplify :
`[ 8^3a xx 2^5 xx 2^(2a) ]/[ 4 xx 2^(11a) xx 2^(-2a) ]`
Simplify:
`[ 3 xx 27^( n + 1 ) + 9 xx 3^(3n - 1 )]/[ 8 xx 3^(3n) - 5 xx 27^n ]`
Simplify:
`( x^a/x^-b )^( a^2 - ab + b^2 ) xx ( x^b/x^-c )^( b^2 - bc + c^2 ) xx ( x^c/x^-a )^( c^2 - ca + a^2 )`
