Advertisements
Advertisements
Question
`[(3/7)^-3]^4` = ______
Options
`(3/7)^-7`
`(3/7)^-10`
`(7/3)^12`
`(3/7)^20`
Advertisements
Solution
`[(3/7)^-3]^4 = bbunderline((7/3)^12)`
Explanation:
`[(3/7)^-3]^4 = (3/7)^(-3(4))` ...[∵ (am)n = amn]
`= (3/7)^-12`
`= (7/3)^12` ....`[∵ (a)^-"n" = 1/"a"^"n"]`
RELATED QUESTIONS
Evaluate :
`3^3 xx ( 243 )^(-2/3) xx 9^(-1/3)`
Evaluate:
`( 27/125 )^(2/3) xx ( 9/25 )^(-3/2)`
Simplify:
`[ 5^( n + 3 ) - 6 xx 5^( n + 1 )]/[ 9 xx 5^n - 5^n xx 2^2 ]`
Evaluate :
`sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3)`
Simplify the following and express with positive index :
`([27^-3]/[9^-3])^(1/5)`
Simplify :
`[ 8^3a xx 2^5 xx 2^(2a) ]/[ 4 xx 2^(11a) xx 2^(-2a) ]`
Simplify:
`[ 3 xx 27^( n + 1 ) + 9 xx 3^(3n - 1 )]/[ 8 xx 3^(3n) - 5 xx 27^n ]`
Simplify:
`( x^a/x^-b )^( a^2 - ab + b^2 ) xx ( x^b/x^-c )^( b^2 - bc + c^2 ) xx ( x^c/x^-a )^( c^2 - ca + a^2 )`
If a = xm + n. yl ; b = xn + l. ym and c = xl + m. yn,
Prove that : am - n. bn - l. cl - m = 1
Find the value of (23)2.
