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Simplify: 5๐‘›+3โˆ’6ร—5๐‘›+19ร—5๐‘›โˆ’5๐‘›ร—2^2 - Mathematics

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Question

Simplify:

`[ 5^( n + 3 ) - 6 xx 5^( n + 1 )]/[ 9 xx 5^n - 5^n xx 2^2 ]`

Simplify
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Solution

`[ 5^( n + 3 ) - 6 xx 5^( n + 1 )]/[ 9 xx 5^n - 5^n xx 2^2 ]`

= `[5^( n + 1 ) xx 5^2- 6 xx 5^( n + 1 )]/[ 9 xx 5^n - 5^n xx 2^2]`

= `[5^( n + 1 ) xx ( 5^2 - 6 )]/[ 5^n xx ( 9 - 4 )]`

= `[5^( n + 1 ) xx ( 25 - 6 )]/[ 5^n xx ( 9 - 4 )]`

= `[5^1 xx 19 ]/5`

= 19

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Laws of Exponents
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Chapter 7: Indices (Exponents) - Exercise 7 (A) [Page 98]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 7 Indices (Exponents)
Exercise 7 (A) | Q 2.3 | Page 98
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