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Question
Simplify :
`( 8x^3 ÷ 125y^3 )^(2/3)`
Sum
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Solution
`( 8x^3 ÷ 125y^3 )^(2/3)`
= `([ 2x xx 2x xx 2x ]/[5y xx 5y xx 5y ])^(2/3)`
= `[((2x)/(5y))^3]^(2/3)`
= `((2x)/(5y))^( 3 xx 2/3 )`
= `((2x)/(5y))^2`
= `[ (2x)/(5y) xx (2x)/(5y) ]`
= `[4x^2]/[25y^2]`
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Laws of Exponents
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