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Question
Simplify the following and express with positive index :
`([27^-3]/[9^-3])^(1/5)`
Sum
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Solution
`([27^-3]/[9^-3])^(1/5)`
= `( 9^3/27^3)^(1/5)`
= `[(3^2)^3/(3^3)^3]^(1/5)`
= `[(3^2/3^3)^3]^(1/5)`
= `[(1/3)^3]^(1/5)`
= `(1/3)^( 3 xx 1/5 )`
= `1/(3)^(3/5)`
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Laws of Exponents
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