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प्रश्न
`[(3/7)^-3]^4` = ______
पर्याय
`(3/7)^-7`
`(3/7)^-10`
`(7/3)^12`
`(3/7)^20`
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उत्तर
`[(3/7)^-3]^4 = bbunderline((7/3)^12)`
Explanation:
`[(3/7)^-3]^4 = (3/7)^(-3(4))` ...[∵ (am)n = amn]
`= (3/7)^-12`
`= (7/3)^12` ....`[∵ (a)^-"n" = 1/"a"^"n"]`
संबंधित प्रश्न
Evaluate:
`5^(-4) xx ( 125)^(5/3) ÷ (25)^(-1/2)`
Simplify :
`( 8x^3 ÷ 125y^3 )^(2/3)`
Simplify :
`( a + b )^(-1) . ( a^(-1) + b^(-1) )`
Evaluate :
`sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3)`
Evaluate:
`(27/8)^(2/3) - (1/4)^-2 + 5^0`
Simplify the following and express with positive index :
`(3^-4/2^-8)^(1/4)`
Simplify:
`[ 3 xx 27^( n + 1 ) + 9 xx 3^(3n - 1 )]/[ 8 xx 3^(3n) - 5 xx 27^n ]`
Show that :
`( a^m/a^-n)^( m - n ) xx (a^n/a^-l)^( n - l) xx (a^l/a^-m)^( l - m ) = 1`
Simplify:
`( x^a/x^b)^( a^2 + ab + b^2 ) xx (x^b/x^c)^(b^2 + bc + c^2) xx (x^c/x^a)^( c^2 + ca + a^2 )`
Find the value of 10−3.
