मराठी

Evaluate: (27125)23×(925)32 - Mathematics

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प्रश्न

Evaluate:

`( 27/125 )^(2/3) xx ( 9/25 )^(-3/2)`

बेरीज
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उत्तर

`( 27/125 )^(2/3) xx ( 9/25 )^(-3/2)`

= `([ 3 xx 3 xx 3 ]/[ 5xx 5 xx 5 ])^(2/3) xx ([ 3 xx 3 ]/[ 5 xx 5 ])^( -3/2 )`

= `[(3/5)^3 ]^(2/3) xx [(3/5)^2]^(-3/2)`

= `(3/5)^( 3 xx 2/3 ) xx (3/5)^( 2 xx - 3/2)`

= `(3/5)^2 xx (3/5)^(-3)`

= `(3/5)^( 2 - 3 )`

= `(3/5)^( -1 )`

= `1/(3/5)`

`= 5/3` 

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Laws of Exponents
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Indices (Exponents) - Exercise 7 (A) [पृष्ठ ९८]

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सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 7 Indices (Exponents)
Exercise 7 (A) | Q 1.3 | पृष्ठ ९८
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