Advertisements
Advertisements
प्रश्न
Evaluate :
`sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3)`
Advertisements
उत्तर
`sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3)`
= `sqrt( 1/2 xx 1/2 ) + ( 0.1 xx 0.1 )^(-1/2) - ( 3 xx 3 xx 3)^(2/3)`
= `1/2 + [(0.1)^2]^(-1/2) - (3^2)^(2/3)`
= `1/2 + ( 0.1 )^( 2 xx (-1/2)) - 3 xx ( 3 xx 2/3 )`
= `1/2 + ( 0.1 )^( - 1) - 3^2`
= `1/2 + 1/0.1 - 9`
= `1/2 + 10/1 - 9`
= `[ 1 + 20 - 18 ]/2`
= `3/2`
= `1 1/2`
APPEARS IN
संबंधित प्रश्न
Evaluate:
`( 27/125 )^(2/3) xx ( 9/25 )^(-3/2)`
Evaluate:
`7^0 xx (25)^(-3/2) - 5^(-3)`
Evaluate:
`(27/8)^(2/3) - (1/4)^-2 + 5^0`
Simplify the following and express with positive index :
`([27^-3]/[9^-3])^(1/5)`
Simplify the following and express with positive index:
`[ 1 - { 1 - ( 1 - n )^-1}^-1]^-1`
If 1960 = 2a. 5b. 7c, calculate the value of 2-a. 7b. 5-c.
Simplify :
`[ 8^3a xx 2^5 xx 2^(2a) ]/[ 4 xx 2^(11a) xx 2^(-2a) ]`
Simplify:
`[ 3 xx 27^( n + 1 ) + 9 xx 3^(3n - 1 )]/[ 8 xx 3^(3n) - 5 xx 27^n ]`
Evaluate the following: `(3^2)^2`
Find the value of (23)2.
