मराठी

Evaluate: 5−4 ×(125)53 ÷(25)−12 - Mathematics

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प्रश्न

Evaluate:

`5^(-4) xx ( 125)^(5/3) ÷ (25)^(-1/2)`

मूल्यांकन
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उत्तर

`5^(-4) xx ( 125)^(5/3) ÷ (25)^(-1/2)`

= `5^(-4) xx ( 5 xx 5 xx 5 )^(5/3) ÷ ( 5 xx 5 )^(-1/2)`

= `5^(-4) xx ( 5^3 )^(5/3) ÷ ( 5^2 )^(-1/2)`

= `5^(-4) xx [( 5)^[3 xx 5/3]] ÷[ ( 5)^[2 xx -1/2]]`

= `[ 5^(-4) xx 5^(5)]/5^(-1)`

= `[5^( 5 - 4 )]/[5^(-1)]`

= `[5^1]/[5^-1]`

= `5^[ 1 - (- 1)]`

= `5^2`
= 5 × 5
= 25

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Laws of Exponents
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Indices (Exponents) - Exercise 7 (A) [पृष्ठ ९८]

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सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 7 Indices (Exponents)
Exercise 7 (A) | Q 1.2 | पृष्ठ ९८
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