Advertisements
Advertisements
प्रश्न
Evaluate :
`3^3 xx ( 243 )^(-2/3) xx 9^(-1/3)`
Advertisements
उत्तर
`3^3 xx ( 243 )^(-2/3) xx 9^(1/3)`
= `3^3 xx ( 3 xx 3 xx 3 xx 3 xx 3 )^( - 2/3 ) xx ( 3 xx 3 )^( -1/3 )`
= `3^3 xx ( 3^5 )^( - 2/3 ) xx ( 3^2 )^(1/3)`
= `3^3 xx 3^( - 10/3 ) xx 3^( -2/3 ) ...[( a^m )^n = a^( mn )]`
= `3^( 3 - 10/3 - 2/3 ) [ a^m xx a^n xx a^o = a^( m + n + o )]`
=`3^([ 9 - 10 - 2]/3)`
= `3^( [9 - 12]/3 )`
= `3^( - 3/3 )`
= `3^-1`
= `1/3`
APPEARS IN
संबंधित प्रश्न
Evaluate:
`7^0 xx (25)^(-3/2) - 5^(-3)`
Evaluate :
`sqrt(1/4) + (0.01)^(-1/2) - (27)^(2/3)`
Simplify the following and express with positive index :
`(3^-4/2^-8)^(1/4)`
Simplify the following and express with positive index :
`([27^-3]/[9^-3])^(1/5)`
Simplify the following and express with positive index:
`[ 1 - { 1 - ( 1 - n )^-1}^-1]^-1`
If 1960 = 2a. 5b. 7c, calculate the value of 2-a. 7b. 5-c.
Simplify:
`( x^a/x^-b )^( a^2 - ab + b^2 ) xx ( x^b/x^-c )^( b^2 - bc + c^2 ) xx ( x^c/x^-a )^( c^2 - ca + a^2 )`
Evaluate the following: `(3^2)^2`
Find the value of 10−3.
Find the value of 46 × 4−4.
